Arrays & Strings

Find the minimum element in a sorted and rotated array.

We will use the principle of binary search [ Complexity :: O(log n) ].
See the implementation below.

using namespace std;

// find the minimum element in rotated and sorted array
int findMin(int arr[],int start,int end) {
   if(start == end) {
      return arr[start];
   int mid = (start+end)/2;
   if(arr[start] > arr[mid]) {
      // min element lies in left subarray
      return findMin(arr,start,mid);
   if(arr[mid] > arr[end]) {
      // min element lies in right subarray
      return findMin(arr,mid+1,end);
   else {
      // array is sorted but not rotated
      return arr[start];

// main
int main() {
   int arr[] = { 3,4,5,6,7,1,2 };
   //int arr[] = { 7,11,15,16};
   int size = sizeof(arr)/sizeof(arr[0]);
   int min = findMin(arr,0,size-1);
   cout<<"\nMinimum element :: "<<min;
   return 0;

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